12/3!×4^5+67-89 == 2026
123/4!×56×7+8+9 == 2026
12×34×5-6-7+8-9 == 2026
1+2+345×6-7×8+9 == 2026
987+65×4!/3×2-1 == 2026
9!/8/7/6+5^4+321 == 2026
9×8-7+654×3-2+1 == 2026
9+8×7+654×3-2+1 == 2026
987+6!+5×4^3-2+1 == 2026
(12-3)×4×56-7+8+9 == 2026
1+2+34×56+7×(8+9) == 2026
Posts by Equitaur
Here's the image that got me banned from facebook.
I'll give a talk on math constants today, 11 AM Chicago time, 18 Dec 2025. You can see the picture of Ford Circles that somehow put me into Facebook Jail. www.youtube.com/watch?v=4cyE...
The cube root of 702331940521262213443072 is 88888888, which equals 70233194+05212622+13443072.
Disney's Pete turns 100! He started as a crossword collector. #art #DaveAlvarez #Disney #puzzle #crossword
2025 = 1³+2³+3³+4³+5³+6³+7³+8³+9³ = (1+2+3+4+5+6+7+8+9)². If you slice the cubes into squares, you can make a side 45 square. This is known as the Partridge problem, and is based on Faulhaber's Formula or Nicomachus's Theorem.
Any centaur, equitaur, taur or hard science fans? My illustrated book is out. www.amazon.com/Non-Sequitur...
Rolling the octahedron produces the Nauru graph
The craziest possible tiling of a plane with similar triangles.
The original solution for the Kirkman Schoolgirl's Problem, by Cayley.
The Plastic Constant
The Doily of Payne
The supergolden ratio